Date: 2018may14 Update: 2025oct20 Language: C/C++ Level: novice Q. C/C++: How to display the 4-digit year? (How to get the 4-digit year into a string) A. Use strftime() or snprintf() as shown in a full example:

#include <time.h> #include <stdio.h> // For snprintf() int main() { struct tm here; const time_t now = time(NULL); localtime_r(&now, &here); // Using strftime() { char buf[100]; strftime(buf, sizeof(buf), "%Y", &here); // You almost certainly don't want %G. printf("year from strftime=%s\n", buf); } // Using snprintf() { char buf[100]; snprintf(buf, sizeof(buf), "%d", here.tm_year + 1900); // Don't forget to add 1900 printf("year from snprintf=%s\n", buf); } }

Output (at one time):

year from strftime=2025 year from snprintf=2025