Date: 2014apr8 Update: 2026sep29 Language: C/C++ Platform: agnostic Q. C/C++: Efficiently loop thru a constant array of strings A. Here is a nice way to do that:

const char *things[] = { "One", "Two", "Three", NULL }; // NULL terminated for (const char **p = things; *p; p++) { printf("thing=%s\n", *p); // Use star-p }

This only works when you can define your own NULL-terminated array. Full Example:

#include <stdio.h> const char *things[] = { "One", "Two", "Three", NULL }; // NULL terminated int main() { for (const char **p = things; *p; p++) { printf("thing=%s\n", *p); // Use star-p } }

Output:

thing=One thing=Two thing=Three