Programming Tips - C/C++: efficiently loop thru a constant array of strings

Date: 2014apr8 Language: C/C++ Platform: agnostic Q. C/C++: efficiently loop thru a constant array of strings A. Here is a nice way do do that:
const char *things[] = { "One", "Two", "Three", NULL }; // NULL terminated for (const char **p = things; *p; p++) { printf("thing=%s\n", *p); // Use star-p }
This only works when you can define your own NULL-terminated array.